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$C 19 O56 
TABLES AND DIAGRAMS 


FOR OBTAINING THE 


Resisting Moments of Eccentric 


Riveted Connections 


E. A. REXFORD 


NEW YORK 
THE ENGINEERING NEWS PUBLISHING COMPANY 
E909 


LI) 


UNIVERSITY 


TABLES AND DIAGRAMS 


FOR OBTAINING THE 


RESISTING MOMENTS OF ECCENTRIC 
RIVETED CONNECTIONS 


NET BOOK NOTICE 


It is intended that this book be sold to the public XFORD 
at the advertised price, and is supplied to the 
trade on terms that will not allow of discount 


The Engineering News Book Dept. 


OF 
CALIFORNMS 


THE ENGINEERING NEWS PUBLISHING COMPANY 
220 BROADWAY, NEW YORK 
1909 


IATA 
a ne 


THATHOD OY 


. Fs 


HOW TO APPLE THE TABLES 


The purpose ot these tables 15 #0 Facihtate fhe operations of obtaining 


the resisting moments of eccentric riveted connections, and 15 in- 


tended especially yor use in designing connections fo columns 


where «eccentric loads are involved. 


a 4 x 


5 flsbelt* 6x4a: 


xx Z 9 


o @# 


The following problem tHlustratas the application of the fab/a: 


1 
i 
! 
| 
| 
i 
‘ 
! 
| 
' 
‘ 
\ 
| 
\ 


to the column and the 


Fuppose we have a boam Framing detpb/eneen // of toe cantar 


hye of the column. and that the reaechion-ot the beam is Suet 


Use a single rew of rivets to connec’ the bracke?’ 


< 
7 


pitch of the rivets will be 3” 


The bad 13 ox trom the center line of the rivers and 


the bending moment 1s therefore 6% x /2000=73500 inch /bs. 


Assume that six rivets are required- Turning to paye 


J we tind thea? fora single row of six rivets with @ 3" pitch the coefficient? 


18 2!, The stress per rivet due te direc? Joad 1s /2000+6 = 2000. Re-~- 


ferring to the ctetch, pagel, and laying off the stress per rive? ave fe direct 
load on the vertical ordinate at the left and then movin 9g paralle/ to 


» ° . oft . * «6 . 
the ebscissae until reaching the 4420 curve, since the rivers are in 


single shear, thence ve rheally downward to the base ine we 


tind that the allowable bending stress on the extreme viva? 1s 


mj wos” Multiplying P/ x GGOO = 8/1900 inch pounds = the resisting 


moment of Phe connection. The bending momenr 1g 732502 


inch pounds, and therefore rhe connection 1s sate. Z rivets wore used 


2o¢g ooF  Ze0oe x 


2stilfnr OG 


Load= 4apoo" 


Rivers 4 “ha 

Assume 20 rivers. 
Stress per river due 
to direct load = 2000” 
Bending ISTOSS OM Ex- 
treme river=2Soo* 
C=86.2 

Resisting Moment = 
86.2x 2900 = 249980 17 1s. 
Bending PTament = 

/0x 22,000= 209,000 1, /bs. 


: The connectron 13 save: 


li may 62 noticed that the two 
6 xing “st'ener® under the beam 
on the column center extend the 
tu// length of the connection 
plate,and embrace al/ the rivets 
in the connection. This 13 done vo 
distribute fhe shear dve #e direct 
Joad wri form ly omeong @ef/ the rivers, 
In this porticuvlar case whore the re- 
sisting roement so greatly exceeds 
the banding moment, the four bottom 
rivers could be omHtad from rhe 
stiBeners and the cannection stil! ba save, 


188388 


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Te. Sy, rapier fay shows rahe wh 


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Stress per rivet due to direct load 


Rat ee 


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CO iftca 2 ae £8 Pe DS 


10 


Bending stress on extreme river 


One Row of Rivers- Uniform Pitch 


Wo. Pins) Po exe ee # 4g at | § 6 
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2 2s 3 3s 4 ZS Sf 6 
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6 | 47% 2/ 24é | 28 YY ae 42 
7138 28 324 | 37%| 22 4c6F| <6 
ee ee iy 36 a2 GE SZ Go 72 
9 | S77 45 52% GO G7E 75 90 
/O GS rd SS 64E 235 82 WF /1o 
tt SS G6 77 88 Re 14° 32 
12 GS 78 Bf JOG. WA S32 O $6 
13 SE 9/1 | 106g | s2s¥ | 1368 | 18/7 | 182 
/Z 87s 10S 1223 140 EIS 475 2/0 
1S 100 4/20 140 /60 /8O 2oo 2goO 
16_\ 743% | 136 | 58#F| SBF | Boa | 226F| 272 
171 727£ | 153 | /78% | 202 | 229% | 255 | 306 
18.| 142% | 17/ J99ZE | 228 256% | 28S | 342 
19.| 158F | s90 | 22/#| 2534 | 2e5 | 3167 | 380 
20\| /75 2/0 245 280 I/F 3250 420° 


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2 Rivers fer row, 
C=7%$0 


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a“ 


Two rows of rivets-2f otc to ctr of rows- Rivets spaced 3°ctr te ctx in the rows. 


Where there 1s one rivet per 


/ River Per row. 


rivet dve to direct lead trom rhe 
C2225 


row to obtain the stress perry. dueto 
bending subtract rhe stress per 
resisting value of the rivet or 
from the bearing valve of ree 


Rivets not staggered. 
plate as ¢he cage may be. 


GO MBBRES WARRE & 1 Hae 
Naw RA A \_\ 


££ ® ®X © YH YF mH N DN OC 


a Rivers per row. 
C=2/60 


3 Rivets Per rom 
C=/3260 


5 : a yoce 
_ ean ED'S 


J. 


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Two rows of rivers- vara ctr ta ctr of rows- Rivers spaced 3 Crr to ctr in the rows. 


Rivers nor 51299 ered. 
JO mae Jo Re 
__——+ a 
HEED “HEED 
4c PN scorer 
= LL =a 
= Be a 
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13 Rivers per row (4 Rivets per row. 
C= /8250 C=2ZU50 
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pT = = es ee ee eis ee }—} 
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6 5 £ 2 ee Se eS ae eS 
1S Rivers perrow /6 Rivers per row 
C= 24/150 C= 273.50 


PLATE 6. 
Two rows of rive #ts- &Z ‘ctr to ete of rews.~ Rivers Spaced 3’ Clr Fo chr in Phe rows. 


Rivers ner staggered. 
2-H 10 (> — 
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= TT | Ni Be ee — a Se 
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ERE ARE 
Re ae | |} |} 
PE Lt Tt tt ttt 
ee Se eer ee oS ee ee 
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/7 Rivers per row /8 Rive?s per rew 
C=30750 C= 343,50 
72 —-—— p< 
: gu 
2 a Be — j BN ee 
ie, Ean 
& q i e ye a a ie a 
————=— ] — » 
7 — e aes *\ 7 = — N 
é PSs IN \ é PS | AY 
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2 ¥ \ 2+ y 
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1/9 Rivers per row 20 Rivarts per row 
C=33/50 C=22/,50 


Be SR a 


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Two rows of rive?ts~3 ctr to chr of rows. Rivers spaced 3 ‘ctr to ctr in the rows. 


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PLATE 


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FLATE II 


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YS rome. 


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Tei 


Two rows of rivers - S; Z 


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FLATE /2 


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Two rows of nvets- 5 ctr 10 ote of roms.- R! vers spaced 3" ctr. ro ctr in the rows. 


| Rivets not staggered 


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PLATE 13 


a” 


Two rows of rivets.- 53 ctr Fe ctr of rows.= Rivets Spaced 3’ctr to ctr in the rows 


Rivers poled staggered. 


iT Beha R sR? 2h RRR 
LeNee Aes SS eeeeoeee 


/8 Rivers Per row 
CH=3BZIDIO 


AX POCA ‘a 
A \ 4 EE 


Or | atily 
COCA ere * 


20 Rivers per row 
C= 427.90 


/7 Rivers Per Fow 
C= 3/3.90 


Ackag Jefe “i 
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C=387.90 


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Three rows of rivets-distances between rows as Shown 
Where rhere 1$ one rive* per 


Rivers spaced 3°crr toctr in the rows. 


row to obtain the stress due to 
tract the stress per rivet dve +o 


bending on the extreme rivet sub- 


direct load from the resistin Gg 


valve of the riveé or trom rhe 


bearing value of rhe plate as 


the case may be. 


=./6./0 
a/ 


4 Rivers per row 


2 Rivers Per row 


C 


CN A SS Se ee 
SEN NNN NS. 


ba ite YEE. kt 


lRiver per row 
3 Rivers per row 
C=27,50 


G= 7 


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‘ % Sit Te EE | eR eae) ee OULD eg OLS ee eee eee ee 7 


Four rows of twers-distances between rows as shown 


Rivets spaced 3"ctr fo cfr in the rows. 


Fg ey eS 


as) 


Oy ae ra Se ee ee eS 


N N 
: 8 8 
. \ \ 
Fb nb E AX WSS SAN SS SX Ny Nt Ni 
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$19.8 8 Bw RUS © Om SG 
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RS SAAR ASA ASS 


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fant hye eh ye 


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i oo 


m™~ 


= 


jo 


qf @k- ¢ = & G =e 


9 


Pee etn + aes 


\ t a ab b % 
NS 665-6 N 
A Ay yay iY ; R 
W_ LP Pees N 
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ae =" 


= a ae 


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a 


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= 


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sat tae ieee a a oie 


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4? 


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GL 


-47 


c> 


“3B 


«@ 


/ 


aF 


/4 Rivers Per row 
C=2Z50.20 


4s-aistances Letweer rows as shown 


Va 


’ 


IIPZ./O 


AAA EAR AAs 


aS Genser eeaneuel 


43 Rivers Per row 


Cc 


Rivers spaced 3"crr fo chr ip Phe rows. 


Four rors of r1 


anv asauuul 
AVA Er) 


IN VXNVAV VY V1 \a8 aaa = 
A\V\\V\\AVV\ lor VV) V1 
AAA NA VAAL VULVA 
PAARL VA AA La) 
OE BAY Ae Se Ree 
AVA GARY AUR 1h S18 WL A 


S$ % ®N 6 H SmHMN A G 


/6 Rivers per row 
C=574.30 


3/0.20 


IS Rivers per row 
c 


ey 


He pas ersen 
| oe a 


ay. 8 2 FR ae oe 
BE Re SS Be 
ay a ak ae: OEY 22s 


Fi 


ae 
U. 


4 i « 
FD kaw mA Sm Y: 


Ey eet re are 


: 


%/ 
a ee, ao 


a. 
pom 
at aaa 


pawns 


thee 


A a Yen a 


VY 
Wy 
fanwant 


YY 
Wwe 
fanwant 


‘ 


four rows of rivets~- Aistances between rows as shown 
ia 


Rivets spaced 3”c7 


Ae A” 
ATV VY Ty |” 
AAA RIAA A ey 


18 Rivets per row. 


C=7/4.30 


Q 
~ 


Ay 
% 
PAG REY 8 0G, 0 CHUB oe th 
ALA ea” 


Lar Aauedanmanae is 
AVVV Vey VTC 
GAN. GHB Lawes 
AVAL A er | er 


. o's 8°. 3 ee Oe SS 


to ctr in the rows. 


JMVMUTiREEyon AGeene om 
Re ce ABW euaceannnenle 


/7 Rivets per row 
C=6$42.30 


(AY QPEL ee ee 
AREER Ae 


a pe ope ae mm amon 


crs per row. 


ve 


’ 


20 R: 
C=870.40 


790.40 


(9 Rivets per row 


ay 


at ak 


" 


% 


F 
JFORNMS 


UNIVERSITY 
= me 


PLATE 24 


Chririvefs=460 


Cc. 


®» ©» Rn © HY Y mA N 


a 


PA AANA AAA A YA Ag 
PAB ABE & eee 
AV PALA | VE 2 Ae Te. 
ABE BRARE fs FEUER EE ZU: 
SBULBRARE! 2H SRR BRER EEE 
So OS ee Ry) ae oe 


C rer 2Zrivers=260 


Hy 


° 
9 


4 


Two rows of rire 4s- 2k ctr to ctr of rows. 
Rive 7s sr2qge red- 2hernate spaces 4b ctr #e ctr 


10 


AA VA VA NAAR A VA VAY. 
AAA AY VV AVA VA 


a Awa SS eS 


Cher 7 rive?e =15: 20 


Cu 


=/LG0 


Cror $ rive?s=E90 


CNN 
wry 


a 


> 


open Ky 


wh, 


CoB me a 


25 


PLATE 


ts ~2% ctr. to ctr of rows. 


ve 


Two rows of ri 


ctr Fo chr 


AL 
fs 


Rivets staggered - clfernate Spaces A 


wikian tor 
Ali tt ler. A 
oe SV OD yo Vancaanendenenn ee 
au’ ane aeReraeny ¥ 9 COS CeCe m2 
AaB Any’ ; ae Anvasc4nne +e 

4 SS % 
OCC ere ce * + ae ‘ i<e 

[Seder ane? cer ccuuet mn : 

Z| 
V y N PCAC AAA . 
\ 
2 > YQ : 
v 9 ‘ rE ee 
a OS Se OP es oe 
g 
%& 

ig Att rer ie 
S 8 es 
0% ary 
N 4 Y 4 
" " % M 

2 , >s 
: N s .s 8 N 
” 5 COT eCe i Lert Cor, i 9 
s « Page 
RCRA scakaeny OCC Cy CCE. mc: Pe 
A FO VY POOLE CECE > a, 


= Sa ee eS ae 


cri a Mee 


four rows of rivers-distances between rows 2-58 - 23 yn ot Bf 55 
Rivets staqgered~ alternate G2IC eS l£ Chr fe ctr 


/ Dpac]e 

/ +e per row 

4 fofd/ ne. of rivers. 
C= /Z./0 


4 “ae F Zz. Zz al 

Sa A eal = i 
. 
Nin ay Fan 
TY b—} 
as Fantas Fa’ 
WEL a 
St ay fant 
< Yo a4 
Pia 74 an 
SEY Ay 5 
Wipy We 

Ww WO 


2 Gpaces 

6= 4ore/ r0. of rivers 

2 rivers in cach ovlside. row. 
/ river » « inside 
C=2330 


10 Wy 

oVWW “ak 
Wy ‘9 
“ 
ZV 8 
MW 
iii 
sly 

7 (SF 

4y 

he 

al 

‘ 3 

“WWe 

Wy, 

oV 

° 

7 Spaces 


S= tora/ ro. of rivers 
2 rivers Por row 
C=27%60 


F FPaACES 

10 = total ro. of rivers 

3 rivers in cach oulsjde row 
oe ae ~ » wside 


C=378O 


i Beane a 
er a mB) . ss . a 
oraee Mc Wey gen Septet 
“5 a4 e445 ‘ é nthe ey ae me 
Joa Rare A ay % ee 


Cae . 
Ges Ne ty ne ui my 
<a eae * 
4 ’ 7 


ty, SR 
one = 


eiapepercey lth FP 


inside 


4 rivets in cach outside row 


Be PACES. 


BF Oe ee ee NS 


/42 total no, of rivers. 


o 


18 = fota/ po. otf rivers. 
5 rivers 12 wach outside row’ 
» wmgide 


oS | PACES. 


D9 ®* KF © HY Fm N SN O 


Z 


3 rivers Per tow 


oe 1 DACES 
G 


Four rows of rivers- distances between rows 24-5F 
Rivets staggered- oternate spaces (2 chr to ofr 


Ge Cr ee Ye wy a Se 


/2 = fofa/ ne. of rivers 


43.Z0 


total ro, of rivers. 
4 rivets Per row. 
C=6/20 


7. FPpaces . 


Natty NANG SEA) “6 SU RAR 


pc in, TEM a” Se Mag, aie EN 


/6 


C= /290 


as. 


te RY 


Cs 


el a i aN Sg gt 8p 


a 


: 
N\ a 
. Q ; 
t Bie: : 
1 NS 
m XW 35 
N a4 u 
Y + 2 + 
N N o> i. ; | 
: se y 8 “ 
Y ae a8 : 
Ss Ae : 
| ss qQg* Q 
: OX Be Sg NY) Rie 8 
Ning A => SS & N : : : 
; Soa ~NN © YQ 
‘) My oe SS RSS, 3 
YN SS BRO AReaN Ae. 3 
\ OO \ 
® 3 SuAuu SUUt.uu Guauuue Ds ce 
; ¥ ™ 
Pkg eo & XN © 
8.9 
ca 
rs X 
.} 
N 
<3 
4 bs . 
% 8 | 
*X Ny 
: 7 “8 
2 W -. ’ 
XS Ry : 
| 3 3 S LO 
Yy * 7 
> _ He 
She gh Ah 
X d Ss» 6 9 ee : 
Se : % be ya 
% ae C88 y TKO 
an A CL. 8 
x ‘ QOAwe Aes OU ABARAT Ae 8 SS. 
Na) HVwWHY : Sieuseutuus 
. 8 § BS 
sts 
w & 


5 amenities nates 


FES 2G 


Y no 


P tai 


-Jp-249.-see page 26 


Ye 


& 


a 


Rivers 371299 ered- oltarnate Spaces 4é ctr fo ctr 


Four rows ot rvers-adistances botweer rows 2 


A \ VY \ \ X\ \ Ser \ Vox \ \ AA on, 
A\\V\\ VY¥\\ VY\ Nox VV AV AA 


Srivets ineach outside row. 


302 fora/ no, of rivers. 
7 


/4 Spaces 


“ 


Trivets per row. 


C=/34,40 


/3 Spaces 
28 =7fotal ne. of rivers. 


BS MSN Oe. Ny Se, HE NS 


ENAVANAC\ AWC. @'AUUP at 
ABVERARS.< Gus sam 


total re. of rivers. 
I rivets in each ovtside row. - 


& 


BOUE DSRS HBB Oe Bape 
KATIA AA 


C=/5090 
/6 Spaces 
IZ 

C=/83 


Dy SRS OS ME Se a 


tota/ 70. of rivers. 
E rivets per row 


ACES 
C=/65.70 


45° Sp 
IZ= 


'. 
q: 
; 


a ee 


y Fane ote An 
+ ig lad 
Be We 


The follewing substitutions can be made without ony appreciable error: 


For two rows of rivets if oo of rows, : | use valves Los rows of rivers 2p “c. to.c. of 


rivers spaced alfernately oa C. xoc. ror rows~ pages 24-25. 
For two rows ) Sf ond <6 + C.4/oC.~ : two rows 53 “c.t0 ¢. of rows- 
is 99 
rivers spaced 2Croc. -not staggered POGES FG %o1F inclusive. 
For four rows Ps 3 “5 ~2f “c.t'0 c.- four rews 24 56-2 ‘C foC. oF 
F é P24 : 
rivers spaced IC *%.- 207 S7AG9 ered rows- pages /9 Pol? inclusive. 
For four rows 24> “f- 2 Cree.e er four rows OFS: ry > oF 2 Foc. oF 
2f-62-Z "6 %0C.+ rivers space oF 99 rews-poges 261029 elusive 


Wternately “S cree. 


2 
Vhe cocthicients, orva/ves of C, represen? the va/ves of 22 where 


of? o,? * a+ cae +a, +d, 13 the sum or the sgvares of the distances of the rivets 
trom the censer oF | ‘gravity of al! the rivets =Zd*, and where = the distance 


of the extreme river From the censer of: ‘gravity ot of the rivers. 
The valve of C fora single row of rivers withea giren voor pireh, az, 
18 to Phe value of C for anorher row oF the same number of rvers, buF 


with 2 agg Z*a, as . a Se asimay 26 _— ads 


wo C ‘= “ = iy - oe ye ve . e ap ae Fe, 
To show that C601 LIF 
Juppose the number of rivers in Coch row to be odd, and +hen +here 
will be » rivets and » egua/ spaces ebore and below she center of 
gravity ofeach row of rwers where the nem berok rivets n-each 


row = 2A+/. 


of xt+ 2k *r5l +--+ Cn-R"+ Fz? 
a nk 
Then = = poreancinneney~ i : 
C af ara” +2 (ata) “+ 3Cera)* Bot #MA-)(Kta) + nara) f 
N(Lta) 
sas AFAR EBR BF EON EE NK 
Ata) + 2(tta)t+3aGata)+r:- ++ t+(n-VD(tra)+n (era) 


Bf 2Gcra)+o-Nara)} nevara) te’ OED; 


Similarly the same rosu// may be ot/aned for arn even number of nvers. 


ee a ee 


In Fhe diagrams the ordinates represen? the vertical shear and 
are ¢hererore drawn rertically. The abscissae represeny the shear 
on ¢he extreme river Ave ro bending, and since this shear ac/s 
perpendicularly to the straigh? line farning the extreme river with 
Phe cerrer oF gravity ok ath ti aeate they are drawn perpend te - 
vlarly to Ahat Are, The distance from the origin of coérdinates 

to the infersection of any ordinate and GLSCISSA represents the 


resultant shear: 


> 


“ty Se a Sila a Pat 


ee age. RAO <e oeety Neer 


Soe BAA Ses <n RE 

=: One 
ow CYS: Rees EO . ba a ee i 
Sess rege ease We. Piss ee ona tas 


AN SHRI 


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